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bisect--helper: convert `vocab_*` char pointers to char arrays

Instead of using a pointer that points at a constant string,
just give name directly to the constant string; this way, we
do not have to allocate a pointer variable in addition to
the string we want to use.

Let's convert `vocab_bad` and `vocab_good` char pointers to char arrays.

Mentored-by: Christian Couder <chriscool@tuxfamily.org>
Signed-off-by: Miriam Rubio <mirucam@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
maint
Miriam Rubio 5 years ago committed by Junio C Hamano
parent
commit
16538bfd2c
  1. 4
      builtin/bisect--helper.c

4
builtin/bisect--helper.c

@ -52,8 +52,8 @@ static void set_terms(struct bisect_terms *terms, const char *bad,
terms->term_bad = xstrdup(bad); terms->term_bad = xstrdup(bad);
} }


static const char *vocab_bad = "bad|new"; static const char vocab_bad[] = "bad|new";
static const char *vocab_good = "good|old"; static const char vocab_good[] = "good|old";


/* /*
* Check whether the string `term` belongs to the set of strings * Check whether the string `term` belongs to the set of strings

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