base_ref_store_init(): remove submodule argument
This is another step towards weakening the 1:1 relationship between ref_stores and submodules. Signed-off-by: Michael Haggerty <mhagger@alum.mit.edu> Reviewed-by: Jeff King <peff@peff.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>maint
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32c597e7b2
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fbfd0a2915
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refs.c
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refs.c
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@ -1477,8 +1477,7 @@ struct ref_store *get_ref_store(const char *submodule)
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}
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void base_ref_store_init(struct ref_store *refs,
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const struct ref_storage_be *be,
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const char *submodule)
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const struct ref_storage_be *be)
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{
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refs->be = be;
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}
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@ -980,7 +980,7 @@ static struct ref_store *files_ref_store_create(const char *submodule)
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struct files_ref_store *refs = xcalloc(1, sizeof(*refs));
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struct ref_store *ref_store = (struct ref_store *)refs;
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base_ref_store_init(ref_store, &refs_be_files, submodule);
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base_ref_store_init(ref_store, &refs_be_files);
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refs->submodule = submodule ? xstrdup(submodule) : "";
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@ -632,12 +632,11 @@ struct ref_store {
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};
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/*
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* Fill in the generic part of refs for the specified submodule and
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* add it to our collection of reference stores.
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* Fill in the generic part of refs and add it to our collection of
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* reference stores.
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*/
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void base_ref_store_init(struct ref_store *refs,
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const struct ref_storage_be *be,
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const char *submodule);
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const struct ref_storage_be *be);
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/*
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* Return the ref_store instance for the specified submodule. For the
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