base_ref_store_init(): remove submodule argument

This is another step towards weakening the 1:1 relationship between
ref_stores and submodules.

Signed-off-by: Michael Haggerty <mhagger@alum.mit.edu>
Reviewed-by: Jeff King <peff@peff.net>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
maint
Michael Haggerty 2017-02-10 12:16:17 +01:00 committed by Junio C Hamano
parent 32c597e7b2
commit fbfd0a2915
3 changed files with 5 additions and 7 deletions

3
refs.c
View File

@ -1477,8 +1477,7 @@ struct ref_store *get_ref_store(const char *submodule)
}

void base_ref_store_init(struct ref_store *refs,
const struct ref_storage_be *be,
const char *submodule)
const struct ref_storage_be *be)
{
refs->be = be;
}

View File

@ -980,7 +980,7 @@ static struct ref_store *files_ref_store_create(const char *submodule)
struct files_ref_store *refs = xcalloc(1, sizeof(*refs));
struct ref_store *ref_store = (struct ref_store *)refs;

base_ref_store_init(ref_store, &refs_be_files, submodule);
base_ref_store_init(ref_store, &refs_be_files);

refs->submodule = submodule ? xstrdup(submodule) : "";


View File

@ -632,12 +632,11 @@ struct ref_store {
};

/*
* Fill in the generic part of refs for the specified submodule and
* add it to our collection of reference stores.
* Fill in the generic part of refs and add it to our collection of
* reference stores.
*/
void base_ref_store_init(struct ref_store *refs,
const struct ref_storage_be *be,
const char *submodule);
const struct ref_storage_be *be);

/*
* Return the ref_store instance for the specified submodule. For the