fetch: convert prune_refs to take a struct refspec

Convert 'prune_refs()' to take a 'struct refspec' as a parameter instead
of a list of 'struct refspec_item'.

Signed-off-by: Brandon Williams <bmwill@google.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>

builtin/fetch.c

@@ -959,11 +959,11 @@ static int fetch_refs(struct transport *transport, struct ref *ref_map)
 	return ret;
 }
 
-static int prune_refs(struct refspec_item *refs, int ref_count, struct ref *ref_map,
-		const char *raw_url)
+static int prune_refs(struct refspec *rs, struct ref *ref_map,
+		      const char *raw_url)
 {
 	int url_len, i, result = 0;
-	struct ref *ref, *stale_refs = get_stale_heads(refs, ref_count, ref_map);
+	struct ref *ref, *stale_refs = get_stale_heads(rs->items, rs->nr, ref_map);
 	char *url;
 	int summary_width = transport_summary_width(stale_refs);
 	const char *dangling_msg = dry_run
@@ -1158,10 +1158,9 @@ static int do_fetch(struct transport *transport,
 		 * don't care whether --tags was specified.
 		 */
 		if (rs->nr) {
-			prune_refs(rs->items, rs->nr, ref_map, transport->url);
+			prune_refs(rs, ref_map, transport->url);
 		} else {
-			prune_refs(transport->remote->fetch.items,
-				   transport->remote->fetch.nr,
+			prune_refs(&transport->remote->fetch,
 				   ref_map,
 				   transport->url);
 		}