usage.c: detect recursion in die routines and bail out immediately
It is theoretically possible for a die handler to get into a state of infinite recursion. For example, if a die handler called another function which itself called die(). Let's at least detect this situation, inform the user, and call exit. Signed-off-by: Brandon Casey <bcasey@nvidia.com> Signed-off-by: Junio C Hamano <gitster@pobox.com>maint
							parent
							
								
									7e2010537e
								
							
						
					
					
						commit
						cd163d4b4e
					
				
							
								
								
									
										15
									
								
								usage.c
								
								
								
								
							
							
						
						
									
										15
									
								
								usage.c
								
								
								
								
							|  | @ -6,6 +6,8 @@ | |||
| #include "git-compat-util.h" | ||||
| #include "cache.h" | ||||
|  | ||||
| static int dying; | ||||
|  | ||||
| void vreportf(const char *prefix, const char *err, va_list params) | ||||
| { | ||||
| 	char msg[4096]; | ||||
|  | @ -82,6 +84,12 @@ void NORETURN die(const char *err, ...) | |||
| { | ||||
| 	va_list params; | ||||
|  | ||||
| 	if (dying) { | ||||
| 		fputs("fatal: recursion detected in die handler\n", stderr); | ||||
| 		exit(128); | ||||
| 	} | ||||
| 	dying = 1; | ||||
|  | ||||
| 	va_start(params, err); | ||||
| 	die_routine(err, params); | ||||
| 	va_end(params); | ||||
|  | @ -94,6 +102,13 @@ void NORETURN die_errno(const char *fmt, ...) | |||
| 	char str_error[256], *err; | ||||
| 	int i, j; | ||||
|  | ||||
| 	if (dying) { | ||||
| 		fputs("fatal: recursion detected in die_errno handler\n", | ||||
| 			stderr); | ||||
| 		exit(128); | ||||
| 	} | ||||
| 	dying = 1; | ||||
|  | ||||
| 	err = strerror(errno); | ||||
| 	for (i = j = 0; err[i] && j < sizeof(str_error) - 1; ) { | ||||
| 		if ((str_error[j++] = err[i++]) != '%') | ||||
|  |  | |||
		Loading…
	
		Reference in New Issue
	
	 Brandon Casey
						Brandon Casey