Browse Source

Show error for 'git merge' with unset merge.defaultToUpstream

'git merge' can be called without any arguments if merge.defaultToUpstream
is set. However, when merge.defaultToUpstream is not set, the user will be
presented the usage information as if he entered a command with a wrong
syntaxis. Ironically, the usage information confirms that no arguments are
mandatory.

This adds a proper error message telling the user why the command failed. As
a side-effect this can help the user in discovering the possibility to merge
with the upstream branch by setting merge.defaultToUpstream.

Signed-off-by: Vincent van Ravesteijn <vfr@lyx.org>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
maint
Vincent van Ravesteijn 13 years ago committed by Junio C Hamano
parent
commit
5480207c4e
  1. 9
      builtin/merge.c

9
builtin/merge.c

@ -1094,9 +1094,12 @@ int cmd_merge(int argc, const char **argv, const char *prefix) @@ -1094,9 +1094,12 @@ int cmd_merge(int argc, const char **argv, const char *prefix)
die(_("You cannot combine --no-ff with --ff-only."));

if (!abort_current_merge) {
if (!argc && default_to_upstream)
argc = setup_with_upstream(&argv);
else if (argc == 1 && !strcmp(argv[0], "-"))
if (!argc) {
if (default_to_upstream)
argc = setup_with_upstream(&argv);
else
die(_("No commit specified and merge.defaultToUpstream not set."));
} else if (argc == 1 && !strcmp(argv[0], "-"))
argv[0] = "@{-1}";
}
if (!argc)

Loading…
Cancel
Save