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A loose object is not corrupt if it cannot be read due to EMFILE 

"git fsck" bails out with a claim that a loose object that cannot be
read but exists on the filesystem to be corrupt, which is wrong when
read_object() failed due to e.g. EMFILE.

Signed-off-by: Junio C Hamano <gitster@pobox.com>
maint
Junio C Hamano 2010-10-28 11:13:06 -07:00
parent b6c4ceccb3
commit 3ba7a06552
1 changed files with 6 additions and 1 deletions
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7
sha1_file.c
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@ -2090,16 +2090,21 @@ void *read_sha1_file_repl(const unsigned char *sha1,
const unsigned char **replacement)
{
const unsigned char *repl = lookup_replace_object(sha1);
void *data = read_object(repl, type, size);
void *data;
char *path;
const struct packed_git *p;

errno = 0;
data = read_object(repl, type, size);
if (data) {
if (replacement)
*replacement = repl;
return data;
}

if (errno != ENOENT)
die_errno("failed to read object %s", sha1_to_hex(sha1));

/* die if we replaced an object with one that does not exist */
if (repl != sha1)
die("replacement %s not found for %s",