block-sha1: make the 'ntohl()' part of the first SHA1 loop
This helps a teeny bit. But what I -really- want to do is to avoid the whole 80-array loop, and do the xor updates as I go along.. Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org> Signed-off-by: Junio C Hamano <gitster@pobox.com>maint
parent
fd536d3439
commit
139e3456ec
|
@ -100,27 +100,31 @@ static void blk_SHA1Block(blk_SHA_CTX *ctx, const unsigned int *data)
|
|||
unsigned int A,B,C,D,E,TEMP;
|
||||
unsigned int W[80];
|
||||
|
||||
for (t = 0; t < 16; t++)
|
||||
W[t] = htonl(data[t]);
|
||||
|
||||
/* Unroll it? */
|
||||
for (t = 16; t <= 79; t++)
|
||||
W[t] = SHA_ROL(W[t-3] ^ W[t-8] ^ W[t-14] ^ W[t-16], 1);
|
||||
|
||||
A = ctx->H[0];
|
||||
B = ctx->H[1];
|
||||
C = ctx->H[2];
|
||||
D = ctx->H[3];
|
||||
E = ctx->H[4];
|
||||
|
||||
#define T_0_19(t) \
|
||||
#define T_0_15(t) \
|
||||
TEMP = htonl(data[t]); W[t] = TEMP; \
|
||||
TEMP += SHA_ROL(A,5) + (((C^D)&B)^D) + E + 0x5a827999; \
|
||||
E = D; D = C; C = SHA_ROR(B, 2); B = A; A = TEMP; \
|
||||
|
||||
T_0_15( 0); T_0_15( 1); T_0_15( 2); T_0_15( 3); T_0_15( 4);
|
||||
T_0_15( 5); T_0_15( 6); T_0_15( 7); T_0_15( 8); T_0_15( 9);
|
||||
T_0_15(10); T_0_15(11); T_0_15(12); T_0_15(13); T_0_15(14);
|
||||
T_0_15(15);
|
||||
|
||||
/* Unroll it? */
|
||||
for (t = 16; t <= 79; t++)
|
||||
W[t] = SHA_ROL(W[t-3] ^ W[t-8] ^ W[t-14] ^ W[t-16], 1);
|
||||
|
||||
#define T_16_19(t) \
|
||||
TEMP = SHA_ROL(A,5) + (((C^D)&B)^D) + E + W[t] + 0x5a827999; \
|
||||
E = D; D = C; C = SHA_ROR(B, 2); B = A; A = TEMP;
|
||||
|
||||
T_0_19( 0); T_0_19( 1); T_0_19( 2); T_0_19( 3); T_0_19( 4);
|
||||
T_0_19( 5); T_0_19( 6); T_0_19( 7); T_0_19( 8); T_0_19( 9);
|
||||
T_0_19(10); T_0_19(11); T_0_19(12); T_0_19(13); T_0_19(14);
|
||||
T_0_19(15); T_0_19(16); T_0_19(17); T_0_19(18); T_0_19(19);
|
||||
T_16_19(16); T_16_19(17); T_16_19(18); T_16_19(19);
|
||||
|
||||
#define T_20_39(t) \
|
||||
TEMP = SHA_ROL(A,5) + (B^C^D) + E + W[t] + 0x6ed9eba1; \
|
||||
|
|
Loading…
Reference in New Issue