@ -5,26 +5,26 @@
@@ -5,26 +5,26 @@
*
* Careful: order of argument flags does matter. For example,
*
* git-checkout-index -a -f file.c
* git checkout-index -a -f file.c
*
* Will first check out all files listed in the cache (but not
* overwrite any old ones), and then force-checkout "file.c" a
* second time (ie that one _will_ overwrite any old contents
* with the same filename).
*
* Also, just doing "git-checkout-index" does nothing. You probably
* meant "git-checkout-index -a". And if you want to force it, you
* want "git-checkout-index -f -a".
* Also, just doing "git checkout-index" does nothing. You probably
* meant "git checkout-index -a". And if you want to force it, you
* want "git checkout-index -f -a".
*
* Intuitiveness is not the goal here. Repeatability is. The
* reason for the "no arguments means no work" thing is that
* from scripts you are supposed to be able to do things like
*
* find . -name '*.h' -print0 | xargs -0 git-checkout-index -f --
* find . -name '*.h' -print0 | xargs -0 git checkout-index -f --
*
* or:
*
* find . -name '*.h' -print0 | git-checkout-index -f -z --stdin
* find . -name '*.h' -print0 | git checkout-index -f -z --stdin
*
* which will force all existing *.h files to be replaced with
* their cached copies. If an empty command line implied "all",
@ -107,7 +107,7 @@ static int checkout_file(const char *name, int prefix_length)
@@ -107,7 +107,7 @@ static int checkout_file(const char *name, int prefix_length)
}
if (!state.quiet) {
fprintf(stderr, "git-checkout-index: %s ", name);
fprintf(stderr, "git checkout-index: %s ", name);
if (!has_same_name)
fprintf(stderr, "is not in the cache");
else if (checkout_stage)