187 lines
3.6 KiB
C
187 lines
3.6 KiB
C
/*
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* Copyright 2008 Jon Loeliger, Freescale Semiconductor, Inc.
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*
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* util_is_printable_string contributed by
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* Pantelis Antoniou <pantelis.antoniou AT gmail.com>
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*
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* This program is free software; you can redistribute it and/or
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* modify it under the terms of the GNU General Public License as
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* published by the Free Software Foundation; either version 2 of the
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* License, or (at your option) any later version.
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*
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* This program is distributed in the hope that it will be useful,
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* but WITHOUT ANY WARRANTY; without even the implied warranty of
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* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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* General Public License for more details.
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*
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* You should have received a copy of the GNU General Public License
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* along with this program; if not, write to the Free Software
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* Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307
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* USA
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*/
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#include <ctype.h>
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#include <stdio.h>
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#include <stdlib.h>
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#include <stdarg.h>
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#include <string.h>
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#include <assert.h>
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#include "util.h"
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char *xstrdup(const char *s)
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{
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int len = strlen(s) + 1;
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char *dup = xmalloc(len);
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memcpy(dup, s, len);
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return dup;
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}
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char *join_path(const char *path, const char *name)
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{
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int lenp = strlen(path);
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int lenn = strlen(name);
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int len;
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int needslash = 1;
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char *str;
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len = lenp + lenn + 2;
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if ((lenp > 0) && (path[lenp-1] == '/')) {
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needslash = 0;
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len--;
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}
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str = xmalloc(len);
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memcpy(str, path, lenp);
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if (needslash) {
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str[lenp] = '/';
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lenp++;
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}
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memcpy(str+lenp, name, lenn+1);
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return str;
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}
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int util_is_printable_string(const void *data, int len)
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{
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const char *s = data;
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const char *ss;
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/* zero length is not */
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if (len == 0)
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return 0;
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/* must terminate with zero */
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if (s[len - 1] != '\0')
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return 0;
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ss = s;
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while (*s && isprint(*s))
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s++;
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/* not zero, or not done yet */
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if (*s != '\0' || (s + 1 - ss) < len)
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return 0;
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return 1;
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}
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/*
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* Parse a octal encoded character starting at index i in string s. The
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* resulting character will be returned and the index i will be updated to
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* point at the character directly after the end of the encoding, this may be
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* the '\0' terminator of the string.
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*/
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static char get_oct_char(const char *s, int *i)
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{
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char x[4];
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char *endx;
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long val;
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x[3] = '\0';
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strncpy(x, s + *i, 3);
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val = strtol(x, &endx, 8);
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assert(endx > x);
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(*i) += endx - x;
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return val;
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}
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/*
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* Parse a hexadecimal encoded character starting at index i in string s. The
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* resulting character will be returned and the index i will be updated to
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* point at the character directly after the end of the encoding, this may be
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* the '\0' terminator of the string.
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*/
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static char get_hex_char(const char *s, int *i)
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{
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char x[3];
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char *endx;
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long val;
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x[2] = '\0';
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strncpy(x, s + *i, 2);
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val = strtol(x, &endx, 16);
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if (!(endx > x))
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die("\\x used with no following hex digits\n");
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(*i) += endx - x;
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return val;
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}
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char get_escape_char(const char *s, int *i)
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{
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char c = s[*i];
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int j = *i + 1;
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char val;
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assert(c);
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switch (c) {
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case 'a':
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val = '\a';
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break;
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case 'b':
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val = '\b';
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break;
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case 't':
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val = '\t';
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break;
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case 'n':
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val = '\n';
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break;
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case 'v':
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val = '\v';
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break;
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case 'f':
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val = '\f';
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break;
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case 'r':
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val = '\r';
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break;
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case '0':
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case '1':
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case '2':
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case '3':
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case '4':
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case '5':
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case '6':
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case '7':
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j--; /* need to re-read the first digit as
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* part of the octal value */
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val = get_oct_char(s, &j);
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break;
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case 'x':
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val = get_hex_char(s, &j);
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break;
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default:
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val = c;
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}
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(*i) = j;
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return val;
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}
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