/* * Copyright 2008 Jon Loeliger, Freescale Semiconductor, Inc. * * util_is_printable_string contributed by * Pantelis Antoniou * * This program is free software; you can redistribute it and/or * modify it under the terms of the GNU General Public License as * published by the Free Software Foundation; either version 2 of the * License, or (at your option) any later version. * * This program is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU * General Public License for more details. * * You should have received a copy of the GNU General Public License * along with this program; if not, write to the Free Software * Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 * USA */ #include #include #include #include #include #include #include "util.h" char *xstrdup(const char *s) { int len = strlen(s) + 1; char *dup = xmalloc(len); memcpy(dup, s, len); return dup; } char *join_path(const char *path, const char *name) { int lenp = strlen(path); int lenn = strlen(name); int len; int needslash = 1; char *str; len = lenp + lenn + 2; if ((lenp > 0) && (path[lenp-1] == '/')) { needslash = 0; len--; } str = xmalloc(len); memcpy(str, path, lenp); if (needslash) { str[lenp] = '/'; lenp++; } memcpy(str+lenp, name, lenn+1); return str; } int util_is_printable_string(const void *data, int len) { const char *s = data; const char *ss; /* zero length is not */ if (len == 0) return 0; /* must terminate with zero */ if (s[len - 1] != '\0') return 0; ss = s; while (*s && isprint(*s)) s++; /* not zero, or not done yet */ if (*s != '\0' || (s + 1 - ss) < len) return 0; return 1; } /* * Parse a octal encoded character starting at index i in string s. The * resulting character will be returned and the index i will be updated to * point at the character directly after the end of the encoding, this may be * the '\0' terminator of the string. */ static char get_oct_char(const char *s, int *i) { char x[4]; char *endx; long val; x[3] = '\0'; strncpy(x, s + *i, 3); val = strtol(x, &endx, 8); assert(endx > x); (*i) += endx - x; return val; } /* * Parse a hexadecimal encoded character starting at index i in string s. The * resulting character will be returned and the index i will be updated to * point at the character directly after the end of the encoding, this may be * the '\0' terminator of the string. */ static char get_hex_char(const char *s, int *i) { char x[3]; char *endx; long val; x[2] = '\0'; strncpy(x, s + *i, 2); val = strtol(x, &endx, 16); if (!(endx > x)) die("\\x used with no following hex digits\n"); (*i) += endx - x; return val; } char get_escape_char(const char *s, int *i) { char c = s[*i]; int j = *i + 1; char val; assert(c); switch (c) { case 'a': val = '\a'; break; case 'b': val = '\b'; break; case 't': val = '\t'; break; case 'n': val = '\n'; break; case 'v': val = '\v'; break; case 'f': val = '\f'; break; case 'r': val = '\r'; break; case '0': case '1': case '2': case '3': case '4': case '5': case '6': case '7': j--; /* need to re-read the first digit as * part of the octal value */ val = get_oct_char(s, &j); break; case 'x': val = get_hex_char(s, &j); break; default: val = c; } (*i) = j; return val; }