Fix util_is_printable_string

The method used did not account for multi-part strings.

Signed-off-by: Pantelis Antoniou <panto@antoniou-consulting.com>
Acked-by: David Gibson <david@gibson.dropbear.id.au>

util.c

@@ -72,7 +72,7 @@ char *join_path(const char *path, const char *name)
 int util_is_printable_string(const void *data, int len)
 {
 	const char *s = data;
-	const char *ss;
+	const char *ss, *se;
 
 	/* zero length is not */
 	if (len == 0)
@@ -82,13 +82,19 @@ int util_is_printable_string(const void *data, int len)
 	if (s[len - 1] != '\0')
 		return 0;
 
-	ss = s;
+	se = s + len;
-	while (*s && isprint(*s))
-		s++;
 
-	/* not zero, or not done yet */
+	while (s < se) {
-	if (*s != '\0' || (s + 1 - ss) < len)
+		ss = s;
-		return 0;
+		while (s < se && *s && isprint(*s))
+			s++;
+
+		/* not zero, or not done yet */
+		if (*s != '\0' || s == ss)
+			return 0;
+
+		s++;
+	}
 
 	return 1;
 }