fs-lib: drop a bashism
Bash 5 apparently longer propagates variable assignments to local variables
in front of function calls when in POSIX mode:
[lkundrak@demiurge ~]$ cat feh.sh
print_VAR () {
echo "$VAR";
}
testfunc () {
local VAR="OLD"
VAR=NEW print_VAR
}
testfunc
[lkundrak@demiurge ~]$ bash4 --posix feh.sh
NEW
[lkundrak@demiurge ~]$ bash5 --posix feh.sh
OLD
[lkundrak@demiurge ~]$ bash5 feh.sh
NEW
[lkundrak@demiurge ~]$
It works the way it did in Bash 4 in non-POSIX mode, for external programs,
or for non-local variables. Don't ask me why -- it's probably some
compatibility thing for some sad old people.
However, this precisely happens when fsck_single() is calling into the
fsck_drv_com(), assigned to _drv by fsck_able(). That ruins the
TEST-70-BONDBRIDGETEAMVLAN test's server and probably more.
Let's pass the fsck driver binary via the function argument instead. It's
less messy anyway.
master
parent
7b76fa924d
commit
43c8c4ce04
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@ -44,22 +44,22 @@ fsck_able() {
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;;
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ext?)
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type e2fsck >/dev/null 2>&1 &&
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_drv="_drv=e2fsck fsck_drv_com" &&
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_drv="fsck_drv_com e2fsck" &&
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return 0
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;;
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f2fs)
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type fsck.f2fs >/dev/null 2>&1 &&
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_drv="_drv=fsck.f2fs fsck_drv_com" &&
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_drv="fsck_drv_com fsck.f2fs" &&
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return 0
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;;
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jfs)
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type jfs_fsck >/dev/null 2>&1 &&
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_drv="_drv=jfs_fsck fsck_drv_com" &&
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_drv="fsck_drv_com jfs_fsck" &&
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return 0
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;;
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reiserfs)
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type reiserfsck >/dev/null 2>&1 &&
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_drv="_drv=reiserfsck fsck_drv_com" &&
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_drv="fsck_drv_com reiserfsck" &&
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return 0
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;;
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btrfs)
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@ -70,12 +70,12 @@ fsck_able() {
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;;
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nfs*)
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# nfs can be a nop, returning success
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_drv="_drv=none :" &&
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_drv=":" &&
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return 0
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;;
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*)
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type fsck >/dev/null 2>&1 &&
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_drv="_drv=fsck fsck_drv_std" &&
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_drv="fsck_drv_std fsck" &&
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return 0
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;;
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esac
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@ -97,6 +97,7 @@ fsck_drv_btrfs() {
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# common code for checkers that follow usual subset of options and return codes
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fsck_drv_com() {
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local _drv="$1"
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local _ret
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local _out
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